JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2023
- Medium
- Numerical
Two convex lenses of focal length \(20\,cm\) each are placed coaxially with a separation of \(60\,cm\) between them. The image of the distant object formed by the combination is at \(...........\,cm\) from the first lens.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(100\)
Step-by-step Solution
Detailed explanation
\(1^{\text {st }}\) refraction in \(L _1\left( I _1\right)\)
\(\frac{1}{ v }-\frac{1}{ u }=\frac{1}{ f }\)
\(\frac{1}{ v }-\frac{1}{\infty}=\frac{1}{ f }\)
\(\therefore v = f\)
\(2^{2 dr } \text { refraction in } L _2\)
\(I _1 \rightarrow \text { object }\)
\(I _2 \rightarrow \text { image }\)
\(u =-40\,cm \quad f =20\,cm\)
\(\frac{1}{ v }-\frac{1}{ u }=\frac{1}{ f }\)
\(\frac{1}{ v }-\frac{1}{(-40)}=\frac{1}{20}\)
\(\frac{1}{ v }=\frac{1}{20}-\frac{1}{40}=\frac{6-3}{120}\)
\(\frac{1}{ v }=\frac{3}{120}=\frac{1}{40}\)
\(\therefore \quad v =40\,cm\)
Correct Answer is \(100.\)
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