JEE Mains · Physics · STD 12 - 13. Nuclei
A nucleus of masss \(M\) emits \(\gamma\)-ray photon of frequency \('v'.\) The loss of internal energy by the nucleus is:
- A \(0\)
- B \({hv}\left[1+\frac{{hv}}{2 {Mc}^{2}}\right]\)
- C \(hv\)
- D \({hv}\left[1-\frac{{hv}}{2 {Mc}^{2}}\right]\)
Answer & Solution
Correct Answer
(B) \({hv}\left[1+\frac{{hv}}{2 {Mc}^{2}}\right]\)
Step-by-step Solution
Detailed explanation
Energy of \(\gamma\, \operatorname{ray}\left[E_{\gamma}\right]=h v\) Momentum of \(\gamma\) ray \(\left[P_{\gamma}\right]=\frac{h}{\gamma}=\frac{h v}{C}\) Total momentum is conserved \(\vec{P}_{\gamma}+\vec{P}_{N u}=0\) Where \(\vec{P}_{N u}=\) Momentum of decayed nuclei…
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