JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2020
- Medium
- MCQ
Two gases-argon (atomic radius \(0.07 \;\mathrm{nm}\),atomic weight \(40\) ) and xenon (atomic radius \(0.1\; \mathrm{nm},\) atomic weight \(140\) ) have the same number density and are at the same temperature. The raito of their respective mean free times is closest to
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(1.09\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2}}\)
\(\tau=\frac{\lambda}{\mathrm{v}}=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2} \mathrm{v}}=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2}} \sqrt{\frac{\mathrm{M}}{3 \mathrm{RT}}}\)
\(\frac{\tau_{1}}{\tau_{2}}=\sqrt{\frac{M_{1}}{M_{2}}} \frac{d_{2}^{2}}{d_{1}^{2}}\)
\(=\sqrt{\frac{40}{140}} \frac{(0.1)^{2}}{(0.07)^{2}}\)
\(=1.09\)
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