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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2020
  • Medium
  • MCQ

Two gases-argon (atomic radius \(0.07 \;\mathrm{nm}\),atomic weight \(40\) ) and xenon (atomic radius \(0.1\; \mathrm{nm},\) atomic weight \(140\) ) have the same number density and are at the same temperature. The raito of their respective mean free times is closest to

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Answer & Solution

Correct Answer

(A) \(1.09\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2}}\)

\(\tau=\frac{\lambda}{\mathrm{v}}=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2} \mathrm{v}}=\frac{1}{\sqrt{2} \pi \mathrm{n}_{\mathrm{v}} \mathrm{d}^{2}} \sqrt{\frac{\mathrm{M}}{3 \mathrm{RT}}}\)

\(\frac{\tau_{1}}{\tau_{2}}=\sqrt{\frac{M_{1}}{M_{2}}} \frac{d_{2}^{2}}{d_{1}^{2}}\)

\(=\sqrt{\frac{40}{140}} \frac{(0.1)^{2}}{(0.07)^{2}}\)

\(=1.09\)

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