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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2023
  • Easy
  • Numerical

A source supplies heat to a system at the rate of \(1000 \,W\). If the system performs work at a rate of \(200\,W\). The rate at which internal energy of the system increases \(.......\,W\)

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Answer & Solution

Correct Answer

(D) \(800\)

Step-by-step Solution

Detailed explanation

\(dQ=dU+dw\)

\(\frac{\mathrm{dU}}{\mathrm{dt}}=\frac{\mathrm{dQ}}{\mathrm{dt}}-\frac{\mathrm{dw}}{\mathrm{dt}}\)

\(\frac{\mathrm{dU}}{\mathrm{dt}}=1000-200=800 \mathrm{~W}\)

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