JEE Mains · Physics · STD 12 - 10. Wave optics
Young's double slit inteference apparatus is immersed in a liquid of refractive index 1.44. It has slit separation of 1.5 mm . The slits are illuminated by a parallel beam of light whose wavelength in air is 690 nm . The fringe-width on a screen placed behind the plane of slits at a distance of 0.72 m , will be _______.
- A 0.23 mm
- B 0.33 mm
- C 0.63 mm
- D 0.46 mm
Answer & Solution
Correct Answer
(A) 0.23 mm
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta W=\frac{\lambda D}{d \cdot \mu}=\frac{690 \times 10^{-9} \times 0.72}{1.5 \times 10^{-3} \times 1.44} \\ & \Rightarrow \Delta W=2.3 \times 10^{-4} \mathrm{~m}=0.23 \mathrm{~mm}\end{aligned}\)
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