JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
Two moles of an ideal gas with \(\frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}=\frac{5}{3}\) are mixed with \(3\) moles of another ideal gas with \(\frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4}{3} .\) The value of \(\frac{\mathrm{C}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}\) for the mixture is
- A \(1.50\)
- B \(1.42\)
- C \(1.45\)
- D \(1.47\)
Answer & Solution
Correct Answer
(B) \(1.42\)
Step-by-step Solution
Detailed explanation
For \(1^{\text {st }}\) gas \(\frac{C_{P_{1}}}{C_{V_{1}}}=\frac{5}{3} \Rightarrow C_{P_{1}}=5 x\) and \(C_{V_{1}}=3 x\) For \(2^{\text {nd }}\) gas \(\frac{C_{P_{2}}}{C_{V_{2}}}=\frac{4}{3} \Rightarrow C_{P_{2}}=4 x\) and \(C_{V_{2}}=3 x\) Now for mixture…
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