JEE Mains · Physics · STD 12 - 12. atoms
The frequency of revolution of the electron in Bohr's orbit varies with \(n\), the principal quantum number as _______.
- A \(\frac{1}{n^4}\)
- B \(\frac{1}{n^2}\)
- C \(\frac{1}{\mathrm{n}}\)
- D \(\frac{1}{n^3}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{n^3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & f=\frac{v}{2 \pi r}=\left(\frac{V_0}{n}\right)\left(\frac{1}{2 \pi r_0 n^2}\right) \\ & f=\frac{V_0}{2 \pi r_0}=\left(\frac{1}{n^3}\right)=f_0\left(\frac{1}{n^3}\right)\end{aligned}\)
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