JEE Mains · Physics · STD 12 -7. Alternating current
In a series \(LCR\) circuit, the inductance, capacitance and resistance are \(L =100\, mH , C =100 \mu F\) and \(R =\) \(10 \Omega\) respectively. They are connected to an \(AC\) source of voltage \(220\, V\) and frequency of \(50\, Hz\). The approximate value of current in the circuit will be.....\(A.\)
- A \(27\)
- B \(89\)
- C \(55\)
- D \(22\)
Answer & Solution
Correct Answer
(D) \(22\)
Step-by-step Solution
Detailed explanation
\(X _{ L }=\omega L =2 \pi \times 50 \times 10^{-1}=10 \pi\) \(X _{ X }=\frac{1}{\omega C }=\frac{1}{2 \pi \times 50} \times 10^{4}=\frac{100}{\pi}\) \(R =10 \Omega\) \(Z =\sqrt{\left(10 \pi-\frac{100}{\pi}\right)^{2}+10^{2}} \simeq 10 \Omega\)…
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