JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
In the diagram shown, the difference in the two tubes of the manometer is \(5\, cm\), the cross section of the tube at \(A\) and \(B\) is \(6\, mm^2\) and \(10\, mm^2\) respectively. The rate at which water flows through the tube is ........ \( cc/s\) \((g\, = 10\, ms^{-2})\)

- A \(7.5\)
- B \(8.0\)
- C \(10.0\)
- D \(12.5\)
Answer & Solution
Correct Answer
(A) \(7.5\)
Step-by-step Solution
Detailed explanation
According to \(Bernoulli's\) theorem, \({p_1} + \frac{1}{2}\rho v_1^2 = {P_2} + \frac{1}{2}\rho v_2^2\) \(\therefore v_2^2 - v_1^2 = 2gh\) \(...\left( 1 \right)\) According to the equation of continuty \({A_1}{v_1} = {A_2}{v_2}\) \(...(2)\)…
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