JEE Mains · Physics · STD 12 - 10. Wave optics
Two coherent sources of light interfere. The intensity ratio of two sources is \(1: 4\). For this interference pattern if the value of \(\frac{I_{\max }+I_{\min }}{I_{\max _{\max }}-I_{\min }}\) is equal to \(\frac{2 \alpha+1}{\beta+3}\), then \(\frac{\alpha}{\beta}\) will be.
- A \(1.5\)
- B \(2\)
- C \(0.5\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(\frac{ I _{1}}{ I _{2}}=\frac{1}{4}\) \(I _{2}=4 I _{1}\) \(I _{\max }= I _{1}+4 I _{1}+2 \sqrt{ I _{1} 4 I _{1}}=9 I _{1}\) \(I_{\min }=I_{1}+4 I_{1}-2 \sqrt{I_{1} 4 I_{1}}=I_{1}\)…
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