JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A block of mass \(200\, g\) is kept stationary on a smooth inclined plane by applying a minimum horizontal force \(F =\sqrt{ x }N\) as shown in figure. The value of \(x =.....\)

- A \(12\)
- B \(82\)
- C \(128\)
- D \(19\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(mg =2 N\) \(\sqrt{ x } \frac{1}{2}=\frac{2 \sqrt{3}}{2}\) \(x =12\)
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