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JEE Mains · Physics · STD 12 - 10. Wave optics

Two light beams of intensities \(4\,I\) and \(9\,I\) interfere on a screen. The phase difference between these beams on the screen at point \(A\) is \(zero\) and at point \(B\) is \(\pi\). The difference of resultant intensities, at the point \(A\) and \(B\), will be \(....I\).

  1. A \(24\)
  2. B \(12\)
  3. C \(6\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(24\)

Step-by-step Solution

Detailed explanation

\(I _{\text {met }}=I_{1}+I_{2}+2 \sqrt{I_{1}} \sqrt{I_{2}} \cos \phi\) \(I_{\max }\) for \(\phi=0 \& I_{\min }\) for \(\phi=\pi\) \(I_{\max }=\left(\sqrt{I_{1}}+\sqrt{I_{2}}\right)^{2}=(\sqrt{9 I}+\sqrt{4 I})^{2}=25\,I\)…
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