JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Three point particles of masses \(1.0\; \mathrm{kg} .1 .5 \;\mathrm{kg}\) and \(2.5\; kg\) are placed at three comers of a right angle triangle of sides \(4.0\; \mathrm{cm}, 3.0 \;\mathrm{cm}\) and \(5.0\; \mathrm{cm}\) as shown in the figure. The center of mass of the system is at a point
- A \(1.5\; cm\) right and \(1.2\; cm\) above \(1\; kg\) mass
- B \(0.9\; cm\) right and \(2.0\; cm\) above \(1\; kg\) mass
- C \(0.6\; cm\) right and \(2.0\; cm\) above \(1\; kg\) mass
- D \(2.0\; cm\) right and \(0.9\; cm\) above \(1\; kg\) mass
Answer & Solution
Correct Answer
(B) \(0.9\; cm\) right and \(2.0\; cm\) above \(1\; kg\) mass
Step-by-step Solution
Detailed explanation
Let \(1 \mathrm{kg}\) as origin and \(\mathrm{x}\) -y axis as shown \({\mathrm{x}_{\mathrm{cm}}=\frac{1(0)+1.5(3)+2.5(0)}{5}=0.9 \mathrm{cm}}\) \({\mathrm{y}_{\mathrm{cm}}=\frac{1(0)+1.5(0)+2.5(4)}{5}=2 \mathrm{cm}}\)
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