JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2020
- Medium
- Numerical
A galvanometer coil has \(500\) turns and each turn has an average area of \(3 \times 10^{-4}\, m ^{2}\). If a torque of \(1.5\,Nm\) is required to keep this coil parallel to magnetic field when a current of \(0.5\, A\) is flowing through it, the strength of the field (in \(T )\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
\(\vec{\tau}=\vec{m} \times \vec{B}\)
\(\tau=N I \times A \times B\)
\(105=500 \times 3 \times 10^{-4} \times \frac{1}{2} \times B\)
\(B=20\)
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