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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2020
  • Medium
  • Numerical

A galvanometer coil has \(500\) turns and each turn has an average area of \(3 \times 10^{-4}\, m ^{2}\). If a torque of \(1.5\,Nm\) is required to keep this coil parallel to magnetic field when a current of \(0.5\, A\) is flowing through it, the strength of the field (in \(T )\) is

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Answer & Solution

Correct Answer

(B) \(20\)

Step-by-step Solution

Detailed explanation

\(\vec{\tau}=\vec{m} \times \vec{B}\)

\(\tau=N I \times A \times B\)

\(105=500 \times 3 \times 10^{-4} \times \frac{1}{2} \times B\)

\(B=20\)

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