JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2020
- Medium
- Numerical
When an object is kept at a distance of \(30\, cm\) from a concave mirror, the image is formed at a distance of \(10\, cm\) from the mirror. If the object is moved with a speed of \(9\, cms ^{-1}\), the speed (in \(cms ^{-1}\) ) with which image moves at that instant is\(....m/s\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{d v}{d t}\right)|=| \frac{v^{2}}{u^{2}}\left|\frac{d u}{d t}\right|\)
\(=\left(\frac{10}{30}\right) 2 \times 9=1 m / s\)
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