JEE Mains · Physics · STD 12 - Magnetism and matter
- JEE Mains 2014
- Medium
- MCQ
The magnetic field of earth at the equator is approximately \(4 \times 10^{-5}\, T\) . The radius of earth is \(6.4 \times 10^6\, m\). Then the dipole moment of the earth will be nearly of the order of
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \({10^{23}}\,A\,{m^2}\)
Step-by-step Solution
Detailed explanation
Given, \(B=4 \times 10^{-5} \,\mathrm{T}\)
\(\mathrm{R}_{\mathrm{E}}=6.4 \times 10^{6}\, \mathrm{m}\)
Dipole moment of the earth \(\mathrm{M}=?\)
\(B = \frac{{{\mu _0}M}}{{4\pi {d^3}}}\)
\(4 \times {10^{ - 5}} = \frac{{4\pi \times {{10}^{ - 7}} \times {\text{M}}}}{{4\pi \times \left( {6.4 \times {{10}^6}} \right.{)^3}}}\)
\(\mathrm{M} \cong 10^{23}\, \mathrm{Am}^{2}\)
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