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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2014
  • Medium
  • MCQ

The magnetic field of earth at the equator is approximately \(4 \times 10^{-5}\, T\) . The radius of earth is \(6.4 \times 10^6\, m\). Then the dipole moment of the earth will be nearly of the order of

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Answer & Solution

Correct Answer

(A) \({10^{23}}\,A\,{m^2}\)

Step-by-step Solution

Detailed explanation

Given, \(B=4 \times 10^{-5} \,\mathrm{T}\)

\(\mathrm{R}_{\mathrm{E}}=6.4 \times 10^{6}\, \mathrm{m}\)

Dipole moment of the earth \(\mathrm{M}=?\)

\(B = \frac{{{\mu _0}M}}{{4\pi {d^3}}}\)

\(4 \times {10^{ - 5}} = \frac{{4\pi  \times {{10}^{ - 7}} \times {\text{M}}}}{{4\pi  \times \left( {6.4 \times {{10}^6}} \right.{)^3}}}\)

\(\mathrm{M} \cong 10^{23}\, \mathrm{Am}^{2}\)

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