JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2022
- Medium
- Numerical
A travelling microscope is used to determine the refractive index of a glass slab. If \(40\) divisions are there in \(1 \; cm\) on main scale and \(50\) Vernier scale divisions are equal to \(49\) main scale divisions, then least count of the travelling microscope is \(\dots \; \times 10^{-6} \; m\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(5\)
Step-by-step Solution
Detailed explanation
\(50 \; VSD =49 \; MSD\)
\(1 \; VSD =\frac{49}{50} \; MSD\)
Least count \(=1 MSD -1 VSD\)
\(=\left(1-\frac{49}{50}\right) MSD =\frac{1}{50} \; MSD\)
\(1 \; MSD =\frac{1}{40} \; cm\)
Least count \(=\frac{1}{50 \times 40} \; cm\)
\(=\frac{1}{2000} cm =\frac{1}{2} \times 10^{-5} \; m\)
\(=0.5 \times 10^{-5} \; m\)
\(=5 \times 10^{-6} \; m\)
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