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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Medium
  • Numerical

A travelling microscope is used to determine the refractive index of a glass slab. If \(40\) divisions are there in \(1 \; cm\) on main scale and \(50\) Vernier scale divisions are equal to \(49\) main scale divisions, then least count of the travelling microscope is \(\dots \; \times 10^{-6} \; m\)

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Answer & Solution

Correct Answer

(D) \(5\)

Step-by-step Solution

Detailed explanation

\(50 \; VSD =49 \; MSD\)

\(1 \; VSD =\frac{49}{50} \; MSD\)

Least count \(=1 MSD -1 VSD\)

\(=\left(1-\frac{49}{50}\right) MSD =\frac{1}{50} \; MSD\)

\(1 \; MSD =\frac{1}{40} \; cm\)

Least count \(=\frac{1}{50 \times 40} \; cm\)

\(=\frac{1}{2000} cm =\frac{1}{2} \times 10^{-5} \; m\)

\(=0.5 \times 10^{-5} \; m\)

\(=5 \times 10^{-6} \; m\)

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