JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2025
- Easy
- MCQ
The unit of \(\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 c}}\) is :
(I = intensity of an electromagnetic wave, \(\mathrm{c}:\) speed of light)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\mathrm{NC}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{I}=\frac{1}{2} \epsilon_0 \mathrm{E}_0^2 \times \mathrm{C} \\
& \mathrm{E}_0=\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 \mathrm{C}}}
\end{aligned}\)
\(E_0\) : electric field N/C
& \mathrm{I}=\frac{1}{2} \epsilon_0 \mathrm{E}_0^2 \times \mathrm{C} \\
& \mathrm{E}_0=\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 \mathrm{C}}}
\end{aligned}\)
\(E_0\) : electric field N/C
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