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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

The unit of \(\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 c}}\) is :
(I = intensity of an electromagnetic wave, \(\mathrm{c}:\) speed of light)

  1. A Vm
  2. B NC
  3. C Nm
  4. D \(\mathrm{NC}^{-1}\)
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Answer & Solution

Correct Answer

(D) \(\mathrm{NC}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{I}=\frac{1}{2} \epsilon_0 \mathrm{E}_0^2 \times \mathrm{C} \\ & \mathrm{E}_0=\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 \mathrm{C}}} \end{aligned}\) \(E_0\) : electric field N/C
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