JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Two coils of self inductance \(L _{1}\) and \(L _{2}\) are connected in series combination having mutual inductance of the coils as \(M\). The equivalent self inductance of the combination will be ...............
- A \(\frac{1}{ L _{1}}+\frac{1}{ L _{2}}+\frac{1}{ M }\)
- B \(L _{1}+ L _{2}+ M\)
- C \(L _{1}+ L _{2}+2 M\)
- D \(L _{1}+ L _{2}-2 M\)
Answer & Solution
Correct Answer
(D) \(L _{1}+ L _{2}-2 M\)
Step-by-step Solution
Detailed explanation
Current on both the inductor is in opposite direction. Hence : \(L _{ eq }= L _{1}+ L _{2}-2 M\)
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