JEE Mains · Physics · STD 12 -7. Alternating current
A sinusoidal voltage of peak value \(283\, V\) and angular frequency \(320/s\) is applied to a series \(LCR\) circuit. Given that \(R\, = 5\,\Omega \) , \(L\,= 25\, mH\) and \(C\, = 1000\, \mu F\). The total impedance, and phase difference between the voltage across the source and the current will respectively be
- A \(10\,\Omega \,\,\) and \(\,\,\,{\tan ^{ - 1}}\left( {\frac{5}{3}} \right)\)
- B \(7\,\Omega \,\,\) and \(45^o\)
- C \(10\,\Omega \,\,\) and \(\,\,\,{\tan ^{ - 1}}\left( {\frac{8}{3}} \right)\)
- D \(7\,\Omega \,\,\) and \(\,\,\,{\tan ^{ - 1}}\left( {\frac{5}{3}} \right)\)
Answer & Solution
Correct Answer
(B) \(7\,\Omega \,\,\) and \(45^o\)
Step-by-step Solution
Detailed explanation
Given, \(\mathrm{V}_{0}=283 \,\mathrm{volt}, \omega=320,\, \mathrm{R}=5 \,\Omega, \mathrm{L}=25 \,\mathrm{mH}, \mathrm{C} =1000 \,\mu \mathrm{F}\) \(x_{L}=\omega L=320 \times 25 \times 10^{-3}=8\, \Omega\)…
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