JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2024
- Hard
- MCQ
The acceleration due to gravity on the surface of earth is \(g\). If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(4 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
\( g=\frac{G M}{R^2} \Rightarrow g \propto \frac{1}{R^2} \)
\( \frac{g_2}{g_1}=\frac{R_1^2}{R_2^2} \)
\( g_2=4 g_1\left(R_2=\frac{R_1}{2}\right)\)
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