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JEE Mains · Physics · STD 11 - 7. gravitation

The acceleration due to gravity on the surface of earth is \(g\). If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :

  1. A \(g / 4\)
  2. B  \(2 \mathrm{~g}\)
  3. C \(g / 2\)
  4. D  \(4 \mathrm{~g}\)
Verified Solution

Answer & Solution

Correct Answer

(D)  \(4 \mathrm{~g}\)

Step-by-step Solution

Detailed explanation

\( g=\frac{G M}{R^2} \Rightarrow g \propto \frac{1}{R^2} \) \( \frac{g_2}{g_1}=\frac{R_1^2}{R_2^2} \) \( g_2=4 g_1\left(R_2=\frac{R_1}{2}\right)\)
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