JEE Mains · Physics · STD 11 - 7. gravitation
The acceleration due to gravity on the surface of earth is \(g\). If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :
- A \(g / 4\)
- B \(2 \mathrm{~g}\)
- C \(g / 2\)
- D \(4 \mathrm{~g}\)
Answer & Solution
Correct Answer
(D) \(4 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
\( g=\frac{G M}{R^2} \Rightarrow g \propto \frac{1}{R^2} \) \( \frac{g_2}{g_1}=\frac{R_1^2}{R_2^2} \) \( g_2=4 g_1\left(R_2=\frac{R_1}{2}\right)\)
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