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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2024
  • Hard
  • MCQ

The acceleration due to gravity on the surface of earth is \(g\). If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :

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Answer & Solution

Correct Answer

(D)  \(4 \mathrm{~g}\)

Step-by-step Solution

Detailed explanation

\( g=\frac{G M}{R^2} \Rightarrow g \propto \frac{1}{R^2} \)

\( \frac{g_2}{g_1}=\frac{R_1^2}{R_2^2} \)

\( g_2=4 g_1\left(R_2=\frac{R_1}{2}\right)\)

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