JEE Mains · Physics · STD 11 - 7. gravitation
Correct formula for height of a satellite from earths surface is _______.
- A \(\left(\frac{T^2 R^2 g}{4 \pi}\right)^{1 / 2}-R\)
- B \(\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{1 / 3}-R\)
- C \(\left(\frac{\mathrm{T}^2 \mathrm{R}^2}{4 \pi^2 \mathrm{~g}}\right)^{1 / 3}-\mathrm{R}\)
- D \(\left(\frac{T^2 R^2}{4 \pi^2}\right)^{-1 / 3}+R\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{1 / 3}-R\)
Step-by-step Solution
Detailed explanation
\(\Rightarrow \frac{\mathrm{GMm}}{(\mathrm{R}+\mathrm{h})^2}=\frac{\mathrm{mv}^2}{(\mathrm{R}+\mathrm{h})}\) \(\Rightarrow \frac{\mathrm{GM}}{(\mathrm{R}+\mathrm{h})}=\mathrm{v}^2 \ldots(1)\) \(\Rightarrow \mathrm{v}=(\mathrm{R}+\mathrm{h}) \omega\)…
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