JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The position of a particle moving on \(x\)-axis is given by \(x(t)=A \sin t+B \cos ^2 t+C t^2+D\), where \(t\) is time. The dimension of \(\frac{A B C}{D}\) is
- A \(L^2 T^{-2}\)
- B \(L^2\)
- C \(L\)
- D \(L^3 \mathrm{~T}^{-2}\)
Answer & Solution
Correct Answer
(A) \(L^2 T^{-2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Dimension }[\mathrm{x}(\mathrm{t})]=[\mathrm{L}] \\ & {[\mathrm{A}]=[\mathrm{L}]} \\ & {[\mathbf{B}]=[\mathrm{L}]} \\ & {[\mathbf{C}]=\left[\mathrm{LT}^{-2}\right]} \\ & {[\mathrm{D}]=[\mathrm{L}]} \\ &…
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