JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2023
- Medium
- MCQ
The speed of a wave produced in water is given by \(v=\lambda^a g^b \rho^c\). Where \(\lambda\), g and \(\rho\) are wavelength of wave, acceleration due to gravity and density of water respectively. The values of \(a , b\) and \(c\) respectively, are
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Answer & Solution
Correct Answer
(A) \(\frac{1}{2}, \frac{1}{2}, 0\)
Step-by-step Solution
Detailed explanation
\(v=\lambda^a g^b \rho^c\)
using dimension formula
\(\Rightarrow\left[ M ^0 L ^1 T ^{-1}\right]=\left[ L ^1\right]^{ a }\left[ L ^1 T ^{-2}\right]^{ b }\left[ M ^1 L ^{-3}\right]^{ c }\)
\(\Rightarrow\left[ M ^0 L ^1 T ^{-1}\right]=\left[ M ^{ c } L ^{ a + b -3 c } T ^{-2 b}\right]\)
\(\therefore c =0, a + b -3 c =1,-2 b =-1 \Rightarrow b =\frac{1}{2}\)
Now \(a+b-3 c=1\)
\(\Rightarrow a+\frac{1}{2}-0=1\)
\(\Rightarrow a=\frac{1}{2}\)
\(\therefore a=\frac{1}{2}, b=\frac{1}{2}, c=0\)
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