JEE Mains · Physics · STD 12 -7. Alternating current
A series \(LCR\) circuit is subjected to an AC signal of \(200 \mathrm{~V}, 50 \mathrm{~Hz}\). If the voltage across the inductor \((\mathrm{L}=10 \mathrm{mH})\) is \(31.4 \mathrm{~V}\), then the current in this circuit is _______.
- A \(68 \mathrm{~A}\)
- B \(63 \mathrm{~A}\)
- C \(10 \mathrm{~A}\)
- D \(10 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(C) \(10 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Voltage across inductor \(\mathrm{V}_{\mathrm{L}}=\mathrm{IX}_{\mathrm{L}}\) \(31.4=\mathrm{I}[\mathrm{L} \omega]\) \(31.4=\mathrm{I}[\mathrm{L}(2 \pi \mathrm{f})]\) \(31.4=\mathrm{I}\left[10 \times 10^{-3}(2 \times 3.14) \times 50\right.\)…
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