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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Two resistances are given as \(R _1=(10 \pm 0.5)\,\Omega\) and \(R_2=(15 \pm 0.5)\, \Omega\). The percentage error in the measurement of equivalent resistance when they are connected in parallel is
- A \(6.33\)
- B \(2.33\)
- C \(4.33\)
- D \(5.33\)
Answer & Solution
Correct Answer
(C) \(4.33\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{ R }=\frac{1}{ R _1}+\frac{1}{ R _2}\) Differentiating both sides, we get \(\frac{\Delta R }{ R ^2}=\frac{\Delta R _1}{ R _1^2}+\frac{\Delta R _2}{ R _2^2}\left[ R =\frac{ R _1 R _2}{ R _1+ R _2}=\frac{10 \times 15}{10+15}=6\right]\)…
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