JEE Mains · Physics · STD 11 - 2. motion in straight line
The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by the object between \(t=0\) to \(t=4 \mathrm{~s}\) ?
- A \(30\mathrm{~m}\)
- B \(11\mathrm{~m}\)
- C \(10\mathrm{~m}\)
- D \(13\mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(30\mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Distance travelled = displacement when direction of velocity remains constant \(\begin{aligned} \Rightarrow \text { Distance } & =\text { Area } \\ & =\frac{1}{2}(2 \mathrm{~s}+4 \mathrm{~s})(10 \mathrm{~m} / \mathrm{s}) \\ & =30 \mathrm{~m}\end{aligned}\)
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