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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2025
  • Easy
  • MCQ

The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by the object between \(t=0\) to \(t=4 \mathrm{~s}\) ?

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Answer & Solution

Correct Answer

(A) \(30\mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Distance travelled = displacement when direction of velocity remains constant
\(\begin{aligned} \Rightarrow \text { Distance } & =\text { Area } \\ & =\frac{1}{2}(2 \mathrm{~s}+4 \mathrm{~s})(10 \mathrm{~m} / \mathrm{s}) \\ & =30 \mathrm{~m}\end{aligned}\)