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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • Numerical

The resistive network shown below is connected to a \(D.C.\) source of \(16\, V\). The power consumed by the network is \(4\, Watt\). The value of \(R\) is ............. \(\Omega\)

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Answer & Solution

Correct Answer

(A) \(8\)

Step-by-step Solution

Detailed explanation

\(P=\frac{16^{2}}{8 R}=4\)

\(\therefore \) \(R=8 \,\Omega\)

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