JEE Mains · Physics · STD 12 - 3. current electricity
The resistive network shown below is connected to a \(D.C.\) source of \(16\, V\). The power consumed by the network is \(4\, Watt\). The value of \(R\) is ............. \(\Omega\)
- A \(8\)
- B \(6\)
- C \(16\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(P=\frac{16^{2}}{8 R}=4\) \(\therefore \) \(R=8 \,\Omega\)
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