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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2024
  • Hard
  • Numerical

Two slits are \(1 \mathrm{~mm}\) apart and the screen is located \(1 \mathrm{~m}\) away from the slits. A light wavelength \(500 \mathrm{~nm}\) is used. The width of each slit to obtain \(10\) maxima of the double slit pattern within the central maximum of the single slit pattern is _______ \(\times 10^{-4} \mathrm{~m}\)

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Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(\mathrm{d}=1 \mathrm{~mm}, \mathrm{D}=1 \mathrm{~m}, \lambda=500 \mathrm{~nm}\)

\(10\left(\frac{\lambda \mathrm{D}}{\mathrm{d}}\right)=\frac{2 \lambda \mathrm{D}}{\mathrm{a}}\)

\(\mathrm{a}=\frac{\mathrm{d}}{5}\)

\(=\frac{10 \times 10^{-4} \mathrm{~m}}{5}\)

\(=2 \times 10^{-4}\)

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