JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2023
- Medium
- MCQ
The initial pressure and volume of an ideal gas are \(P_0\) and \(V_0\). The final pressure of the gas when the gas is suddenly compressed to volume \(\frac{ V _0}{4}\) will be (Given \(\gamma=\) ratio of specific heats at constant pressure and at constant volume)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(P _0(4)^\gamma\)
Step-by-step Solution
Detailed explanation
As gas is suddenly compressed, the processes is adiabatic.
Equation of gas for adiabatic process is
\(PV ^\gamma=\text { constant. }\)
\(\Rightarrow P _1 V _1^\gamma= P _2 V _2^\gamma\)
\(\Rightarrow P _0 V _0^\gamma= P _2\left(\frac{ V _0}{4}\right)^\gamma\)
\(\Rightarrow P _2= P _0(4)^\gamma\)
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