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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2022
  • Hard
  • Numerical

A mass \(0.9\,kg\), attached to a horizontal spring, executes \(SHM\) with an amplitude \(A _{1}\). When this mass passes through its mean position, then a smaller mass of \(124\,g\) is placed over it and both masses move together with amplitude \(A _{2}\). If the ratio \(\frac{ A _{1}}{ A _{2}}\) is \(\frac{\alpha}{\alpha-1}\), then the value of \(\alpha\) will be\(......\)

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Answer & Solution

Correct Answer

(C) \(16\)

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Detailed explanation

\(\frac{1}{2} kA ^{2}=\frac{ p ^{2}}{2\,m }\)

\(\Rightarrow\left(\frac{ A _{1}}{ A _{2}}\right)^{2}=\frac{ m _{2}}{ m _{1}}=\frac{1024}{900}\)

\(\Rightarrow \frac{ A _{1}}{ A _{2}}=\frac{32}{30}=\frac{16}{15}=\frac{16}{16-1}\)

\(\therefore \alpha=16\)

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