JEE Mains · Physics · STD 12 - 5. Magnetism and matter
The relationship between the magnetic susceptibility \((\chi)\) and the magnetic permeability \((\mu)\) is given by :
(\(\mu_0\) is the permeability of free space and \(\mu_{\mathrm{r}}\) is relative permeability)
- A \(\chi=\frac{\mu}{\mu_0}-1\)
- B \(\chi=\frac{\mu_{\mathrm{r}}}{\mu_0}+1\)
- C \(\chi=\mu_{\mathrm{r}}+1\)
- D \(\chi=1-\frac{\mu}{\mu_0}\)
Answer & Solution
Correct Answer
(A) \(\chi=\frac{\mu}{\mu_0}-1\)
Step-by-step Solution
Detailed explanation
We have \(\begin{aligned} & \mu_{\mathrm{r}}=(1+\chi) \Rightarrow \chi=\left(\mu_{\mathrm{r}}-1\right) \\ & \mu=\mu_0 \mu_{\mathrm{r}} \Rightarrow \mu_{\mathrm{r}}=\frac{\mu}{\mu_0} \\ & \therefore \chi=\left(\frac{\mu}{\mu_0}-1\right)\end{aligned}\)
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