JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The dimension of stopping potential \(\mathrm{V}_{0}\) in photoelectric effect in units of Planck's constant \(h\), speed of light \(c\) and Gravitational constant \(G\) and ampere \(A\) is
- A \(\mathrm{h}^{2} \mathrm{G}^{3 / 2} \mathrm{C}^{1 / 3} \mathrm{A}^{-1}\)
- B \(\mathrm{h}^{-2 / 3} \mathrm{c}^{-1 / 3} \mathrm{G}^{4 / 3} \mathrm{A}^{-1}\)
- C \(\mathrm{h}^{1 / 3} \mathrm{G}^{2 / 3} \mathrm{c}^{1 / 3} \mathrm{A}^{-1}\)
- D \(\mathrm{h}^{0} \mathrm{c}^{5} \mathrm{G}^{-1} \mathrm{A}^{-1}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{h}^{0} \mathrm{c}^{5} \mathrm{G}^{-1} \mathrm{A}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{v}_{0}=\mathrm{h}^{\mathrm{x}} \mathrm{c}^{\mathrm{y}} \mathrm{G}^{\mathrm{z}} \mathrm{A}^{\mathrm{w}}\)…
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