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JEE Mains · Physics · STD 11 - Friction
  • JEE Mains 2023
  • Medium
  • MCQ

A block of mass \(m\) slides down the plane inclined at angle \(30^{\circ}\) with an acceleration \(\frac{ g }{4}\). The value of coefficient of kinetic friction will be :

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Answer & Solution

Correct Answer

(B) \(\frac{1}{2 \sqrt{3}}\)

Step-by-step Solution

Detailed explanation

\(Mg \sin 30^{\circ}-\mu mg \cos 30^{\circ}= ma\)

\(\frac{g}{2}-\frac{\sqrt{3}}{2} \cdot \mu g=\frac{g}{4}\)

\(\frac{\sqrt{3}}{2} \mu=\frac{1}{4}\)

\(\mu=\frac{1}{2 \sqrt{3}}\)

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