JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2021
- Hard
- Numerical
The potential energy \((U)\) of a diatomic molecule is a function dependent on \(r\) (interatomic distance) as \(U =\frac{\alpha}{ r ^{10}}-\frac{\beta}{ r ^{5}}-3\) where, \(\alpha\) and \(\beta\) are positive constants. The equilibrium distance between two atoms will be \(\left(\frac{2 \alpha}{\beta}\right)^{\frac{a}{b}},\) where a \(=\) ..........
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
For equilibrium
\(\frac{ dU }{ dr }=0\)
\(\frac{-10 \alpha}{r^{11}}+\frac{5 \beta}{r^{6}}=0\)
\(\frac{5 \beta}{r^{6}}=\frac{10 \alpha}{r^{11}}\)
\(r ^{3}=\frac{2 \alpha}{\beta}\)
\(r=\left(\frac{2 \alpha}{\beta}\right)^{\frac{1}{3}}\)
\(a=1\)
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