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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

The potential energy \((U)\) of a diatomic molecule is a function dependent on \(r\) (interatomic distance) as \(U =\frac{\alpha}{ r ^{10}}-\frac{\beta}{ r ^{5}}-3\) where, \(\alpha\) and \(\beta\) are positive constants. The equilibrium distance between two atoms will be \(\left(\frac{2 \alpha}{\beta}\right)^{\frac{a}{b}},\) where a \(=\) ..........

  1. A \(2\)
  2. B \(1\)
  3. C \(3\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

For equilibrium \(\frac{ dU }{ dr }=0\) \(\frac{-10 \alpha}{r^{11}}+\frac{5 \beta}{r^{6}}=0\) \(\frac{5 \beta}{r^{6}}=\frac{10 \alpha}{r^{11}}\) \(r ^{3}=\frac{2 \alpha}{\beta}\) \(r=\left(\frac{2 \alpha}{\beta}\right)^{\frac{1}{3}}\) \(a=1\)
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