ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2021
  • Hard
  • Numerical

The potential energy \((U)\) of a diatomic molecule is a function dependent on \(r\) (interatomic distance) as \(U =\frac{\alpha}{ r ^{10}}-\frac{\beta}{ r ^{5}}-3\) where, \(\alpha\) and \(\beta\) are positive constants. The equilibrium distance between two atoms will be \(\left(\frac{2 \alpha}{\beta}\right)^{\frac{a}{b}},\) where a \(=\) ..........

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

For equilibrium

\(\frac{ dU }{ dr }=0\)

\(\frac{-10 \alpha}{r^{11}}+\frac{5 \beta}{r^{6}}=0\)

\(\frac{5 \beta}{r^{6}}=\frac{10 \alpha}{r^{11}}\)

\(r ^{3}=\frac{2 \alpha}{\beta}\)

\(r=\left(\frac{2 \alpha}{\beta}\right)^{\frac{1}{3}}\)

\(a=1\)

Same subject
Explore more questions on app