JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2025
- Medium
- MCQ
A particle moves along the \(x\)-axis and has its displacement \(x\) varying with time \(t\) according to the equation \(\mathrm{x}=\mathrm{c}_0\left(\mathrm{t}^2-2\right)+\mathrm{c}(\mathrm{t}-2)^2\) where \(c_0\) and \(c\) are constants of appropriate dimensions. Then, which of the following statements is correct?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) the acceleration of the particle is \(2\left(c+c_0\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{v}=\frac{\mathrm{dx}}{\mathrm{dt}}=2 \mathrm{tC}_0+2 \mathrm{C}(\mathrm{t}-2) \\ & \mathrm{a}=\frac{\mathrm{dv}}{\mathrm{dt}}=2 \mathrm{C}_0+2 \mathrm{C}\end{aligned}\)
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