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JEE Mains · Physics · STD 12 - 3. current electricity

In the given circuit ' \(a\) ' is an arbitrary constant. The value of \(m\) for which the equivalent circuit resistance is minimum, will be \(\sqrt{\frac{ x }{2}}\). The value of \(x\) is ...........

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(R =\left(\frac{ ma }{3}\right)+\left(\frac{ a }{2 m }\right)\) \(\frac{ dR }{ dm }=\frac{ a }{3}-\frac{ a }{2 m ^{2}}=0\) \(\frac{ a }{3}=\frac{ a }{2 m ^{2}}\) \(m ^{2}=\frac{3}{2}\) \(m =\sqrt{\frac{3}{2}}\) \(x =3\)
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