JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
The solid cylinder of length \(80\, {cm}\) and mass \({M}\) has a radius of \(20\, {cm}\). Calculate the density of the material used if the moment of inertia of the cylinder about an axis \(CD\) parallel to \({AB}\) as shown in figure is \(2.7\, {kg} {m}^{2}\)

- A \(14.9\)
- B \(75\)
- C \(750\)
- D \(149\)
Answer & Solution
Correct Answer
(D) \(149\)
Step-by-step Solution
Detailed explanation
Parallel axis theorem \({I}={I}_{{CM}}+{Md}^{2}\) \({I}=\frac{{Mr}^{2}}{2}+{M}\left(\frac{{L}}{2}\right)^{2}\) \(2.7={M} \frac{(0.2)^{2}}{2}+{M}\left(\frac{0.8}{2}\right)^{2}\) \(2.7={M}\left[\frac{2}{100}+\frac{16}{100}\right]\) \({M}=15\, {kg}\)…
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