JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
Identify the operation performed by the circuit given below

- A \(AND\)
- B \(NAND\)
- C \(OR\)
- D \(NOT\)
Answer & Solution
Correct Answer
(A) \(AND\)
Step-by-step Solution
Detailed explanation
\(A\) \(B\) \(C\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A tank with a small hole at the bottom has been filled with water and kerosene (specific gravity \(0.8\)). The height of water is \(3\,m\) and that of kerosene \(2\,m\). When the hole is opened the velocity of fluid coming out from it is nearly ........ \(ms^{-1}\) .(take \(g\, = 10\, m s^{-2}\) and density of water \(= 10^3\, kg\, m^{-3}\))JEE Mains 2014 Medium
- A potential barrier of \(0.4 \,V\) exists across a p-n junction. An electron enters the junction from the \(n\)-side with a speed of \(6.0 \times 10^{5} \,ms ^{-1}\). The speed with which electron enters the \(p\) side will be \(\frac{x}{3} \times 10^{5} \,ms ^{-1}\) the value of \(x\) is .............. (Given mass of electron \(=9 \times 10^{-31} \,kg\), charge on electron \(=1.6 \times 10^{-19} \,C\).)JEE Mains 2022 Hard
- Your friend is having eye sight problem. She is not able lo see clearly a distant uniform window mesh and it appears to her as non-uniform and distorted. The doctor diagnosed the problem asJEE Mains 2021 Medium
- in circular plate of mass \(M\) and radius \(R\) has its density varying as \(p\left( r \right) = {p_0}\,r\) with \(P_0\) as constant and \(r\) is the distance from its center. The moment of Inertia of the circular plate about an axis perpendicular to the plate and passing through its edge is \(I = aMR^2\) . The value of the coefficient \(a\) isJEE Mains 2019 Hard
- In finding out refractive index of glass slab the following observations were made through travelling microscope \(50\) vernier scale division \(=\) \(49 \mathrm{MSD} ; 20\) divisions on main scale in each \(\mathrm{cm}\) For mark on paper \(\mathrm{MSR}=8.45 \mathrm{~cm}, \mathrm{VC}=26\) For mark on paper seen through slab \(\mathrm{MSR}=7.12 \mathrm{~cm}, \mathrm{VC}=41\) For powder particle on the top surface of the glass slab \(\mathrm{MSR}=4.05 \mathrm{~cm}, \mathrm{VC}=1\) \((\mathrm{MSR}=\) Main Scale Reading, \(\mathrm{VC}=\) Vernier Coincidence) Refractive index of the glass slab is _______.JEE Mains 2024 Hard
- A particle is moving in a circular path of radius a under the action of an attractive potential \(U = - \frac{k}{{2{r^2}}}\) Its total energy isJEE Mains 2018 Medium
More PYQs from JEE Mains
- This question has statement \(1\) and statement \(2\) . Of the four choices given after the statements, choose the one that best describes the two statements.
Statement \(- 1\): A point particle of mass m moving with speed \(u\) collides with stationary point particle of mass \(M\). If the maximum energy loss possible is given as \(f\) \(\left( {\frac{1}{2}m{v^2}} \right)\) then \( f = \left( {\frac{m}{{M + m}}} \right)\) Statement \(-2\): Maximum energy loss occurs when the particles get stuck together as a result of the collision.JEE Mains 2013 Medium - Let \(\vec a,\,\vec b,\) and \(\vec c\) be three unit vectors, out of which vectors \(\vec b\) and \(\vec c\) are non-parallel. If \(\alpha \) and \(\beta \) are the angles which vector \(\vec a\) makes with vectors \(\vec b\) and \(\vec c\) respectively and \(\vec a\,\, \times \,\,(\vec b\,\, \times \,\,\vec c)\,\, = \,\,\frac{1}{2}\,\,\vec b,\) then \(\left| {\alpha - \beta } \right|\) is equal to .............. \(^o\)JEE Mains 2019 Hard
- Let \(\alpha\) and \(\beta\) be real numbers. Consider a \(3 \times 3\) matrix \(A\) such that \(A ^2=3 A +\alpha I\). If \(A ^4=21 A +\beta I\), thenJEE Mains 2023 Hard
- A particle of mass \(10\,g\) moves in a straight line with retarcation \(2x\), where \(x\) is the displacement in \(SI\) units. Its loss of kinetic energy for above displacement is \(\left(\frac{10}{x}\right)^{- n }\, J\). The value of \(n\) will be \(............\).JEE Mains 2023 Hard
- A capacitor is connected to a \(20\, {V}\) battery through a resistance of \(10\, \Omega .\) It is found that the potential difference across the capacitor rises to \(2\, {V}\) in \(1\, \mu {s}\). The capacitance of the capacitor is \(....\,\mu {F}\) Given : \(\ln \left(\frac{10}{9}\right)=0.105\)JEE Mains 2021 Hard
- \(\lim _{n \rightarrow \infty} \frac{1}{2^{n}}\left(\frac{1}{\sqrt{1-\frac{1}{2^{a}}}}+\frac{1}{\sqrt{1-\frac{2}{2^{n}}}}+\frac{1}{\sqrt{1-\frac{3}{2^{a}}}}+\ldots \ldots+\frac{1}{\sqrt{1-\frac{2^{a}-1}{2^{n}}}}\right)\) is equal toJEE Mains 2022 Hard