JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A closed circular tube of average radius \(15\,cm\), whose inner walls are rough, is kept in vertical plane. A block of mass \(1\,kg\) just fit inside the tube. The speed of block is \(22\,m / s\), when it is introduced at the top of tube. After completing five oscillations, the block stops at the bottom region of tube. The work done by the tube on the block is \(......J\). [Given \(g=10\,m / s ^2\) ]
- A \(+564\)
- B \(-879\)
- C \(-986\)
- D \(-245\)
Answer & Solution
Correct Answer
(D) \(-245\)
Step-by-step Solution
Detailed explanation
\(r _{\text {avg }}=15\,cm\) \(w _{ f }+ w _{ g }=\Delta KE\) \(w _{ f }+10 \times 0.3=-\frac{1}{2} \times 484\) \(w _{ f }=-245\,J\)
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