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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2024
  • Hard
  • MCQ

The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly _______.

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Verified Solution

Answer & Solution

Correct Answer

(D) \(12.1 \mathrm{eV}\)

Step-by-step Solution

Detailed explanation

\(E_n = -\frac{13.6}{n^2} \, \mathrm{eV}\)

\(\Delta E = E_3 - E_1\)

\(\Delta E = \left(-\frac{13.6}{3^2}\right) - \left(-\frac{13.6}{1^2}\right)\)

\(\Delta E = 13.6 \left(1 - \frac{1}{9}\right) = 13.6 \left(\frac{8}{9}\right) \approx 12.089 \, \mathrm{eV}\)

\(\Delta E \approx 12.1 \, \mathrm{eV}\)

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