JEE Mains · Physics · STD 12 - 12. atoms
The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly _______.
- A \(1.5 \mathrm{eV}\)
- B \(13.6 \mathrm{eV}\)
- C \(1.9 \mathrm{eV}\)
- D \(12.1 \mathrm{eV}\)
Answer & Solution
Correct Answer
(D) \(12.1 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
\(E_n = -\frac{13.6}{n^2} \, \mathrm{eV}\) \(\Delta E = E_3 - E_1\) \(\Delta E = \left(-\frac{13.6}{3^2}\right) - \left(-\frac{13.6}{1^2}\right)\) \(\Delta E = 13.6 \left(1 - \frac{1}{9}\right) = 13.6 \left(\frac{8}{9}\right) \approx 12.089 \, \mathrm{eV}\)…
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