JEE Mains · Physics · STD 11 - 11. thermodynamics
The heat absorbed by a system in going through the given cyclic process is _______.
- A \(61.6 \mathrm{~J}\)
- B \(431.2 \mathrm{~J}\)
- C \(616 \mathrm{~J}\)
- D \(19.6 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(61.6 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{U}=0 \text { (Cyclic process) }\) \(\Delta \mathrm{Q}=\mathrm{W}=\text { area of } \mathrm{P}-\mathrm{V} \text { curve. }\) \(=\pi \times\left(140 \times 10^3 \mathrm{~Pa}\right) \times\left(140 \times 10^{-6} \mathrm{~m}^3\right)\)…
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