JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Three capacitors \({C}_{1}=2\, \mu {F}, {C}_{2}=6 \, \mu {F}\) and \({C}_{3}=12 \, \mu {F}\) are connected as shown in figure. Find the ratio of the charges on capacitors \({C}_{1}, {C}_{2}\) and \({C}_{3}\) respectively:
- A \(2: 1: 1\)
- B \(2: 3: 3\)
- C \(1: 2: 2\)
- D \(3: 4: 4\)
Answer & Solution
Correct Answer
(C) \(1: 2: 2\)
Step-by-step Solution
Detailed explanation
\(\left(V_{D}-V\right) C_{2}+\left(V_{D}-0\right) C_{3}=0\) \(\left(V_{D}-V\right) 6+\left(V_{D}-0\right) 12=0\) \(V_{D}-V+2 V_{D}=0\) \(V_{D}=\frac{V}{3}\) \({q}_{2}=\left({V}-{V}_{{D}}\right) {C}_{2}=\left({V}-\frac{{V}}{3}\right)(6 \mu {F})\) \({q}_{2}=(4 {V}) \mu {F}\)…
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