JEE Mains · Physics · STD 12 - 12. atoms
The radius of third stationary orbit of electron for Bohr's atom is \(R\). The radius of fourth stationary orbit will be:
- A \(\frac{4}{3} \mathrm{R}\)
- B \(\frac{16}{9} R\)
- C \(\frac{3}{4} R\)
- D \(\frac{9}{16} R\)
Answer & Solution
Correct Answer
(B) \(\frac{16}{9} R\)
Step-by-step Solution
Detailed explanation
\( \mathrm{r} \propto \frac{\mathrm{n}^2}{\mathrm{Z}} \) \( \frac{\mathrm{r}_4}{\mathrm{r}_3}=\frac{4^2}{3^2} \) \( \mathrm{r}_4=\frac{16}{9} \mathrm{R}\)
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