JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2023
- Easy
- Numerical
The distance travelled by a particle is related to time \(t\) as \(x =4 t ^2\). The velocity of the particle at \(t =\) \(5 s\) is \(.........ms^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
\(x =4 t ^2\)
\(v =\frac{ dx }{ dt }=8 t\)
At \(t =5\,sec\)
\(v =8 \times 5=40\,m / s\)
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