JEE Mains · Physics · STD 11 - 2. motion in straight line
The distance travelled by a particle is related to time \(t\) as \(x =4 t ^2\). The velocity of the particle at \(t =\) \(5 s\) is \(.........ms^{-1}\)
- A \(40\)
- B \(25\)
- C \(20\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
\(x =4 t ^2\) \(v =\frac{ dx }{ dt }=8 t\) At \(t =5\,sec\) \(v =8 \times 5=40\,m / s\)
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