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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2023
  • Easy
  • Numerical

The distance travelled by a particle is related to time \(t\) as \(x =4 t ^2\). The velocity of the particle at \(t =\) \(5 s\) is \(.........ms^{-1}\)

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Answer & Solution

Correct Answer

(A) \(40\)

Step-by-step Solution

Detailed explanation

\(x =4 t ^2\)

\(v =\frac{ dx }{ dt }=8 t\)

At \(t =5\,sec\)

\(v =8 \times 5=40\,m / s\)

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