JEE Mains · Physics · STD 11 - 3.2 motion in plane
The maximum vertical height to which a man can throw a ball is \(136\,m\). The maximum horizontal distance upto which he can throw the same ball is \(.....\,m\)
- A \(192\)
- B \(136\)
- C \(272\)
- D \(68\)
Answer & Solution
Correct Answer
(C) \(272\)
Step-by-step Solution
Detailed explanation
\(H _{\max }=\frac{ v ^2}{2 g }=136\,m\) \(R _{\max }=\frac{ v ^2}{ g }=2 H _{\max }\) \(=2(136)\) \(=272\,m\)
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