The magnetic field in a travelling electromagnetic wave has a peak value of \(20\ n T\). The peak value of electric field strength is......\(Vm^{-1}\)

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(B) \(6 \)

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From question,

\(\mathrm{B}_{0}=20 \mathrm{nT}=20 \times 10^{-9}\, \mathrm{T}\)

(\(\because\) velocity of light in vacuum \(\mathrm{C}=3 \times 10^{8}\, \mathrm{\,ms}^{-1}\))

\( \overrightarrow{\mathrm{E}}_{0} =\overrightarrow{\mathrm{B}}_{0} \times \overrightarrow{\mathrm{C}} \)

\( | \overrightarrow{\mathrm{E}}_{0} =|\overrightarrow{\mathrm{B}}| \cdot|\overrightarrow{\mathrm{C}}|=20 \times 10^{-9} \times 3 \times 10^{8} \)

\(=6 \,\mathrm{V} / \mathrm{m} \)

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