JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2023
- Medium
- MCQ
The initial speed of a projectile fired from ground is \(u\). At the highest point during its motion, the speed of projectile is \(\frac{\sqrt{3}}{2} u\). The time of flight of the projectile is:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\frac{ u }{ g }\)
Step-by-step Solution
Detailed explanation
\(u \cos \theta=\frac{\sqrt{3} u }{2} \Rightarrow \cos \theta=\frac{\sqrt{3}}{2}\)
\(\Rightarrow \theta=30^{\circ}\)
\(T =\frac{2 u \sin 30^{\circ}}{ g }=\frac{ u }{ g }\)
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