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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2023
  • Medium
  • MCQ

The initial speed of a projectile fired from ground is \(u\). At the highest point during its motion, the speed of projectile is \(\frac{\sqrt{3}}{2} u\). The time of flight of the projectile is:

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Answer & Solution

Correct Answer

(B) \(\frac{ u }{ g }\)

Step-by-step Solution

Detailed explanation

\(u \cos \theta=\frac{\sqrt{3} u }{2} \Rightarrow \cos \theta=\frac{\sqrt{3}}{2}\)

\(\Rightarrow \theta=30^{\circ}\)

\(T =\frac{2 u \sin 30^{\circ}}{ g }=\frac{ u }{ g }\)

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