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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2023
  • Easy
  • MCQ

The temperature of an ideal gas is increased from \(200\,K\) to \(800\,K\). If r.m.s. speed of gas at \(200\,K\) is \(v_0\). Then, r.m.s. speed of the gas at \(800\,K\) will be:

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Answer & Solution

Correct Answer

(D) \(2 v _0\)

Step-by-step Solution

Detailed explanation

\(V _{ rms }=\sqrt{\frac{3 RT }{ M }}\)

\(\Rightarrow V _{ rms } \alpha \sqrt{ T }\)

Increasing temperature \(4\) times, rms speed gets doubled.

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