JEE Mains · Physics · STD 11 - 13. oscillations
A particle undergoing simple harmonic motion has time dependent displacement given by \(x(t)\, = \,A\,\sin \,\frac{{\pi t}}{{90}}\). The ratio of kinetic to potential energy \(o\) the particle at \(t=210\,s\) will be
- A \(1/9\)
- B \(1\)
- C \(2\)
- D \(0.33\)
Answer & Solution
Correct Answer
(D) \(0.33\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}=\frac{1}{2} \mathrm{mv}^{2} ; \mathrm{U}=\frac{1}{2} \mathrm{k} \mathrm{x}^{2}=\frac{1}{2} \mathrm{m}^{2} \mathrm{x}^{2}\)…
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